QUESTION
Objective Question
If the reduced bearing of a line AB is N60° W and length is 100 m, then the latitude and departure of the line AB will be,
Answer
( Option C)
+ 50 m, - 86.6 m
Solution
Whole circle bearing WCB = 360° - 60° - 300°
Latitude = L cos θ = 100 cos 300°
= +50 m
Departure =L sin θ = 100 sin 300°
= - 86.6 m
