ABCD is a four-bar mechanism in which AB = 30 cm and CD = 45 cm. At an instant, both AB and CD are perpendicular to fixed link AD. If velocity of B at this condition is V, then velocity of C is:
V
V
According to question,
When both links AB and CD are at 900
VB = VC
Vc = V
Velocity diagram would be a straight
line 
..Method 2..
Now finding
By theorem of angular velocity
Now,
Hence, the correct option is (D).
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