The power
developed by a turbine in a certain steam power plant is 1206 kW. The heat
supplied to the boiler is 3500 kJ/kg. The heat rejected by steam to cooling
water is 2900 kJ/kg. The feed pump work required to condensate back into the
boiler is 6 kW. What will be mass flow rate of cycle?
0.00622 kg/s
2 kg/s
6.22 kg/s
0.002 kg/s
2 kg/s
Given :
Power
developed
Feed pump
work required
Heat supplied
Heat rejected
We know that
Wnet = (Qspply - Qrejected) X m
(Wturbine -Wpump) = (Qspply - Qrejected) X m
1206-6 =
(3500-2900) × m
m = 
kg/s
Hence, the
correct option is (B).
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