+91-9828-747676
Question
A beam of length (L + 2a) has supports 'L' aparts with an overhang 'a' on each side. The beam carries a concentrated load 'W' at each end. The shear force between the two supports is given by:
(L + 2a) yEckbZ dh ,d /kju dh 'L' dh vkyEc ds vfrfjDr izR;sd fn'kk eas vfryVd 'a' dh vkyEc gSA /kju ds izR;sd fljs ij ladsfUnzr Hkkj 'W' gSA nks vkyEcksa ds chp vi:i.k cy gksrk gSA
A.
Zero
B.
0.5 W
C.
W
D.
2W
Answer ( Option A)

Zero

Solution

RA + RB = 2W
From symmetry, RA = RB 
So,
                           2RA = 2W
                          RAW = RB 
Shear force between supports A & B
Fx = –W + RA = –W + W = 0
So, Shear force between support A & B is zero
Also we can analyse it by shear force diagram of Beam. 

Popular Online Test Serie

Preparing students for success in a changing World.

RPSC-AE

RPSC-AE
RSSB-JE

RSSB-JE
SSC-JE

SSC-JE
RRB-JE/SSE

RRB-JE/SSE
RSEB-JE/AE

RSEB-JE/AE
DRDO CEPTAM -10 (STA-B)

DRDO CEPTAM -10 (STA-B)

ISRO Scientist Engineer

ISRO Scientist Engineer
View All

Online Classes

We care about our students

View More


banner
banner
banner
banner
banner
Online Classes
Register Now
Test Series
Register Now
Job Notification
Job Notification

Daily Quiz

RPSC-AE, RSMSSB-JE, SSC-JE, RRB-JE, PSU's