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Question
A rectangular 230 mm × 350 mm beam is (effective depth). The factored shear force acting at a section is 80 kN. If the permissible shear stress in concrete is 0.25 MPa, the design shear force is nearly
A.
100 kN
B.
80 kN
C.
60 kN
D.
20 kN
Answer ( Option C)

60 kN

Solution

Shear force resisted by concrete section only (Fc)
= 230 × 350 × 0.25 × 10-3 
= 20.125 kN
Design shear force (that will be resisted by shear stirrups)
Fd = factored shear force – Fc 
Fd = 80 – 20.125
Fd = 59.875 kN
Fd ≈ 60 kN

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