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Question
A tape of length and weight w kg/m is suspended at its ends with a pull of P kg, the sag correction is: 
YkECkkbZ vkSj w kg/m Hkkj ds ,d Vsi dks P kg dk f[akpko mlds Nksjksa ij fuyfEcr fd;k tkrk gSA >ksy la'kks/u gS%
A.
B.
C.
D.
Answer ( Option A)

Solution

Tape length of tape suspended between support = l
Weight of tape per unit length (w) = w kg/m
Total weight (w) = w × l
pull applied = p

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