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Question
An open-coiled helical spring of wire diameter 12 mm. mean coil radius 84 mm, helix angle 60° carries an axial load of 480 N. What is the twisting moment?
A.
10.22 Nm
B.
20.16 Nm
C.
14.24 Nm 
D.
24.11 Nm
Answer ( Option B)

20.16 Nm

Solution

Given:
d = 12 mm, R = 84 mm
∝= 60°, P = 480 N
For open-coiled helical spring with mean radius R subjected to axial load P
                   
Torque(T) = PR cos ∝
Bending moment (M) = PR sin ∝
T = PR cos ∝
⇒T = 480 × 84 × cos60°
⇒T = 20.16 N-m

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