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Question
Calculate the combined correction for curvature and refraction (in m) for a distance of 2 km.
2 fdyksehVj nwjh ds fy, oØrk vkSj viorZu (ehVj esa) ds fy, la;qDr lq/kj dh x.kuk dhft,A
A.
0.045
B.
0.135
C.
0.269
D.
3.14
Answer ( Option C)

0.269

Solution

CC = Combined correction 0.0673 × d2
d = distance in km
CC = 0.0673 × (2)2 0.269

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