For
maximum power transmitted by belt, the maximum permissible tension in the belt
is
बेल्ट द्वारा प्रेषित अधिकतम शक्ति के लिए, बेल्ट में अधिकतम अनुमेय तनाव है
Equal
to centrifugal tension
Twice the centrifugal tension
Thrice
the centrifugal tension
Four
times the centrifugal tension
Thrice
the centrifugal tension
Let
T1 = tension in the tight
side,
Now, we know that
The power transmitted by a belt is given by
P = ( T1 - T2 )v
Putting values from eqn. (i)
Tmax = Maximum tension to which the belt can be subjected, thus eqn. (ii) can be written as
For maximum power we need to differentiate the equation (iii) w.r.t v and equate it to zero.
Hence, the
correct option is (C).
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