For the circuit shown below, voltage V1 will be
2.64
3.64
V
6.0 V
9.1
V
6.0 V
The direction of the current flow is shown in figure below :
Applying KCL (Kirchhoff’s Current Law) at node x, we have,
Similarly, applying KCL at nodey,
On solving equation (i) and (ii), we get
Hence, the correct option is (C).
&Key Points:-
Kirchhoff’s
current law states that for a parallel path, the total current entering the
circuit’s junction is exactly equal to the total current leaving the same
junction.
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