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Question
If the percentage of soil passing 0.075 mm sieve is 65%, its liquid limit is 45% and its plastic limit is 20%, then as per IS soil classification system, the soil would be
A.
MI
B.
CI
C.
CL
D.
CH
Answer ( Option B)

CI

Solution

Given % of soil particle Passing through 0.075 mm Sieve=65%
WL = 45%
WP = 20%
So, IP = 45 - 20 = 25%
Equation of A-Line Plasticity index i.e. IP, 
IP=0.73 (WL - 20)
So, IP of A-Line is 
IP = 0.73 (WL - 20) = 0.73 (45 - 20) =18.25% > 7%
Given soil IP is greater than A-Line IP
Hence, soil is inorganic clay i.e. C
Liquid limit, of 45% lies between 35-50%, hence, soil is medium compressible i.e. I
so soil is CI

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