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Question
If the reduced bearing of a line AB is N 60° W and length is 100 m, then the latitude and departure of the line AB wil be,
A.
+50 m, +86.6 m
B.
+70.7 m, –50.0 m
C.
+50 m, –86.6 m
D.
+86.6 m, –50.0 m
Answer ( Option C)

+50 m, –86.6 m

Solution

∴  Latitude = + 100 cos 60°
    = + 50 m
∴ Departure = – 100 sin60°
   = – 86.6 m

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