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Question

If the wheelbase, the pivot center, and wheel track of the are 2.5 m, 1.1 m, and 1.3 m respectively. The angle of the inside lock is 42℃. What is the circle radius of the outer front wheel?

यदि व्हीलबेस, पिवट सेंटर और व्हील ट्रैक क्रमशः 2.5 मीटर, 1.1 मीटर और 1.3 मीटर हैं। आंतरिक लॉक का कोण 42℃ है। बाहरी फ्रंट व्हील की सर्कल त्रिज्या क्या है?

A.

2.6 m

B.

3.6 m

C.

4.6 m

D.

1.6 m

Answer ( Option B)

3.6 m

Solution

  • Explanation:
  • b = wheelbase = 2.5 m,
  • c = pivot center = 1.1 m,
  • a = wheel track = 1.3 m, and
  • θ = angle of inside lock = 42℃.
  • For the inner front wheel,

radius =bsinθac2=2.5sin421.31.12 = 3.6 m

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