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Question
Pick up the correct option from the following for the beam as shown in the figure
(1) MAB = 0 
(2) MAB = MBA 
(3) MBA + MBC = 0 
(4) MCB = 0
 
A.
1 and 3 are correct
B.
2 and 3 are correct
C.
only 4 is correct
D.
only 3 is correct
Answer ( Option A)

1 and 3 are correct

Solution

FBD of the beam above will be
Consider FBD of members AB, BC & Joint B 
Joint 'B' is in rotational equilibrium. Therefore for Joint B summation of all moments about B is zero i.e. 
∑MB = 0
⇒MBA + MBC = 0
Also, 'A' is hinged support by definition of hinge support, the B.M at A will be zero. 
i.e. MAB = 0

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