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Question
The bearing of a line AB is 162°30' and the angle ABC is 115°15'. The baring of line BC will be
AB js[kk dk fnd~eku 162°30' vkSj dks.k ABC 115°15 rks BC js[kk dk fnd~eku gksxkA
A.
277°–45'
B.
97°–45'
C.
47°–15'
D.
295°–15'
Answer ( Option B)

97°–45'

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