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Question
The condition for greatest hydraulic efficiency of some of the cross-sections of the channel is that the hydraulic radius must be equal to half of the depth. Which one of the following cross-sections does not satisfy the above condition?
A.
Trapezoidal channel
B.
Triangular channel
C.
Rectangular channel
D.
Semicircular channel
Answer ( Option B)

Triangular channel

Solution

(1)    Most efficient Trapezoidal channel is half of the regular hexagon
                     
(2)    For most efficient triangular channel
Vortex angle = 90°
Top width,   T = 2y
(3)    For most efficient rectangular channel
                         
(4)    For most efficient semicircular channel
           
                   

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