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Question
The domestic sewage of a town was tested for total solids and the following results were obtained: 
Weight of sample of sewage = 1000 gm 
Weight of solids after evaporation of liquid = 0.952 gm 
Weight of dry residue after ignition = 0.516 gm 
What is the value of volatile solids?
A.
952 ppm
B.
516 ppm
C.
436 ppm
D.
694 ppm
Answer ( Option C)

436 ppm

Solution

Weight of water
= 1000 – 0.952
= 999.048 gm
= 999.048 cm3 
= 0.99 lit  1 lit
Weight of volatile solids
= 0.952 – 0.516
= 0.436 gm
= 436 mg
Concentration of volatile solids
= 436 ppm

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