The food compartment of a refrigerator is maintained at 4°C by removing heat from it at a rate of 360 kJ/min. If the required power input to the refrigerator is 2 kW, the COP of the refrigerator is:
एक रेफ्रिजरेटर के खाद्य डिब्बे को 360 kJ/मिनट की दर से गर्मी हटाकर 4°C पर बनाए रखा जाता है। यदि रेफ्रिजरेटर के लिए आवश्यक पावर इनपुट 2 किलोवाट है, तो रेफ्रिजरेटर का COP है:
2.0
1/3
0.5
3.0
3.0
Given :Cooling
load (Q) =360 kJ/min
Power (W) = 2
kW
Cooling load (Q) of the refrigerator to kW
..Method 1..
We know that
Coefficient of performance 
Hence the COP
is 3.
Hence, the correct option is (D).
Cooling load
of refrigeration,
Power input (P)
= 2 kW
Coefficient
of performance
Hence, the
correct option is (D).
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