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Question
The whole circle bearing of line AB is 50° and line BC is 120°. The defection angle at B from AB to BC is
A.
70°
B.
50°
C.
110°
D.
120°
Answer ( Option A)

70°

Solution

The deflection angle at B from AB to BC is 
Δ = 120° – 50°
   = 70°

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