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Question
What is the value of resultant retardation in m/s2 when a longitudinal friction coefficient of 0.36 is allowed for stopping the vehicle on road?
A.
1.24
B.
1.82
C.
2.24
D.
3.53
Answer ( Option D)

3.53

Solution

Given -
f = 0.36
 
So, a = f × g = 0.36 × 9.81 = 3.53

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